Question

Sulfur dioxide gas, a form of smog, is formed when sulfur burms with oxygen from the air. How many liters of sulfur dioxide gas would be released at STP if we burned 2.50 moles of sulfur with plenty of oxygen? ​

Answer 1

The amount of sulfur dioxide gas released at STP would be 22.4 liters, which is calculated using the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the universal gas constant, and T is temperature. In this case, n = 2.50 moles, R = 0.0821 L·atm/mol·K, T = 273 K (0°C), and P = 1 atm. Thus, V = (2.50 mol)(0.0821 L·atm/mol·K)(273 K)/(1 atm) = 22.4 L.

Step-by-step explanation: