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What is the square root of a number equal to?

User MayDaniel
by
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1 Answer

4 votes

Answer:

Step-by-step explanation:

(sqrt(n-1)) = (n+3)/4

sqr both sides

n-1 = (n^2 + 6n + 9) / 16

16n -16 = (n^2 + 6n + 9)

(n^2 + 6n + 9) -16n +16 =0

n^2 - 10n + 25 = 0

(n - 5)(n - 5) = 0

n-5 = 0

n=5

check:

4(sqrt(5-1)) = (5+3)

4(sqrt(4)) = 8

4(2) = 8

8 = 8

User Meeeee
by
7.5k points