Question

What is an equation of the line that passes through the points (-5, -6) and (5, 6)?

Answer 1

y =
`(6)/(5)` x

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 5, - 6 ) and (x₂, y₂ ) = (5, 6 )

m =
`(6-(-6))/(5-(-5))` =
`(6+6)/(5+5)` =
`(12)/(10)` =
`(6)/(5)` , then

y =
`(6)/(5)` x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation.

using (5, 6 ) , then

6 = 6 + c ⇒ c = 6 - 6 = 0

y =
`(6)/(5)` x ← equation of line