Question

1-) drawing the following triangle in the cartesian plane The vertices of the triangle are the points A (3,2); B (2,0); and C (-1,-4).2-) use the distance fórmula to find the length of the following line segments or side of your triangle above AB= distance 1 =called. d¹?=CA distance 2 = called d²? BC = distance 3 = called d³?

Answer 1

We have to draw the triangle with vertices:

`\begin{gathered} A(3,2) \\ B(2,0) \\ C(-1,-4) \end{gathered}`

For doing so, we will draw the points A, B, and C on the plane, and we will trace segments from A to B, from B to C, and from C to A.

We remember that for locating a point in the plane, we call the first number the x-coordinate and the second number the y-coordinate. We locate the x-coordinate on the x-axis and the y-coordinate on the y-axis, and the intersection will be the point desired.

Having this in mind, we obtain:

And joining the segments, the triangle obtained is: