Question

11. An object of mass 3.123 kg is being pulled by ahorizontal force of 210 N on a horizontal force.The coefficient of kinetic friction betwedsthe object and the surface is 0.1. Calculate theacceleration of the object. (1 point)30.373 m/s²A.B. O 66.263 m/s²2C. O 122.405 m/sD. 110.843 m/sE. 088.439 m/s²Submit Query

Answer 1

11.

Apply Newton's law:

∑F = m a

Where:

F = forces

F = 210 N

Fr = friction force = N u

u= coefficient of friction = 0.1

m= mass = 3.123 kg

a = acceleration

N = normal force = mg

g= gravity = 9.8 m/s^2

N = 3.123 kg x 9.8 m/s^2 = 30.6054 N

FR = N u = 30.6054 N x 0.1 = 3.06054 N

∑F = m a

F - Fr = ma

210 N - 3.06054 N = 3.123 kg (a)

206.93946 = 3.123 kg (a)

a = 206.93946 N / 3.123 kg

a = 66.263 m/s^2 (option B)