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5 votes
Solve this system of linear equations:
3
4x - 2y = 8
Y=2x=2

User Sun Junwen
by
7.7k points

1 Answer

2 votes

Answer:

no solutions

Explanation:

4x - 2y = 8

y = 2x - 2

4x - 2(2x - 2) = 8 ==> substitute y = 2x - 2 for y in the equation 4x - 2y = 8.

4x - 2*2x - 2*(-2) = 8 ==> distribute 2 to 2x and -2

4x - 4x - (-4) = 8 ==> simplify

0 - (-4) = 8

0 + 4 = 8 ==> subtracting a negative number is equivalent to adding by a

positive number

4 = 8 ==> 4
\\eq 8, so the system of equations has no solutions

User Andrews B Anthony
by
7.4k points