Question

Given 8, p,q,s,t,1/4 are the first six terms of geometric progression. Find the value p,q,r,s and t?

Answer 1

p=4

q=2

s=1

t=1/2

Explanation:

8,p,q,s,t,1/4

number of terms=6

first term a=8

last term a_{n}=1/4

`a_(n)=ar^(n-1)\\(1)/(4)=8(r)^(6-1)\\(1)/(32)=r^5\\((1)/(2))^5=r^5\\r=(1)/(2)\\p=8* r=8 * ((1)/(2))=4\\q=pr=4 *((1)/(2))=2\\s=qr\\s=2 * ((1)/(2))=1\\t=sr\\=1 * ((1)/(2))=(1)/(2)`