Answer:
Therefore, the derivative of y with respect to x is 0 if 2^xy=1.
Explanation:
ln(2^xy) = ln(1)
Using the logarithmic identity:
ln(b^x) = x*ln(b)
We can simplify the equation to:
xy*ln(2) = 0
Since ln(2) is not equal to zero, we can divide both sides of the equation by ln(2) to get:
xy = 0
The derivative of y with respect to x is given by:
dy/dx = 0
Therefore, the derivative of y with respect to x is 0 if 2^xy=1.