Problem
We have the following inequality given:
8x +4 > 20
OR
-6x+3 >= -3
Solution
For this case we can start with the first inequality and we got:
We can subtract 4 in both sides
8x > 20-4
8x >16
And now we can divide both sides by 8
x > 2
-6x +3 >= -3
If we subtract 3 in both sides we got:
-6x >= -6
And dividing by -6 in both sides we got:
x <1
So then on interval notation we got: