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A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 64 ft/s. How high will it go? Use - 32 ft/s2 forthe acceleration caused by gravity. Ignore air resistance.

A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 64 ft-example-1
User Yodi
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1 Answer

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23 votes

Given,

The initial height of the ball, h₁=6 ft

The initial velocity of the ball, u=64 ft/s

The acceleration due to gravity, g=-32 ft/s²

The velocity of the ball when it reaches the maximum height will be, v=0 ft/s

From the equation of motion,


v^2-u^2=2gh_2

Where h₂ is the height covered by the ball to reach the maximum height.

On substituting the known values,


\begin{gathered} 0-64^2=2*-32* h_2 \\ h_2=(-64^2)/(2*-32) \\ =64\text{ ft} \end{gathered}

Thus the maximum height reached by the ball is


\begin{gathered} H=h_1+h_2 \\ =6+64 \\ =70\text{ ft} \end{gathered}

Thus the maximum height reached by the ball is 70 ft

User JustinLovinger
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