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4 votes
Explain why the order of the coordinates does not matter when calculating length in geometry?

User Andresf
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2 Answers

3 votes

P(x_1;\ y_1);\ Q(x_2;\ y_2)\\\\|PQ|=√((x_2-x_1)^2+(y_2-y_1)^2)\\\\|QP|=√((x_1-x_2)^2+(y_1-y_2)^2)=√([-1(x_2-x_1)]^2+[-1(y_2-y_1)]^2)\\\\=√((-1)^2(x_2-x_1)^2+(-1)^2(y_2-y_1)^2)=√((x_2-x_1)^2+(y_2-y_1)^2)\\\\|PQ|=|QP|
User Jonney
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8.2k points
6 votes

A=(x_1,y_1)\ \ \ and\ \ \ B=(x_2,y_2)\\\\|AB|= √((x_1-x_2)^2+(y_1-y_2)^2) =\\\\= √([-(x_2-x_2)]^2+[-(y_2-y_1)]^2)=\\\\ =√((x_2-x_2)^2+(y_2-y_1)^2)=|BA|
User Sorrat
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8.1k points