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42 votes
42 votes
Hi someone please help me and thanks have a great day. Hi can help with questions 4.Hi someone please help me and thanks have a great day.Hi someone please help me and thanks have a great day.

User SaphuA
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1 Answer

11 votes
11 votes

we have:

arc NPL = 2 arcNL


\begin{gathered} arcNPL+arcNL=360 \\ 2\text{arcNL}+\text{arcNL}=360 \\ 3\text{arcNL}=360 \\ (3)/(3)\text{arcNL}=(360)/(3) \\ \text{arcNL}=120 \\ \end{gathered}

then


\text{arcNPL}=2(120)=240

therefore:


\angle NML=(1)/(2)arcNPL=(1)/(2)(240)=120

answer: (3) 120°

User Gabriel Hautclocq
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