Question

If a woman is homozygous for type A blood and her husband is type O, what is the probability that their offspring would have any one of the 4 possible blood types.

Answer 1

The offspring would have type A blood group.

The genotype of mother would be
`I^(A)I^(A)` (homozygous type A blood group).

Thus, she will produce only one type of gamete that is,
`I^(A)`.

Similarly, the genotype of a the father would be ii (type O blood group).

He will also produce only one type of gamete that is, i.

The cross would produce offspring with genotype
`I^(A)i`.

Thus, the offspring would have only type A blood group.

Hence, the probability of having blood group A would be 100% and probability of having other blood group (B, AB or O) would be zero %.

Answer 2

The four blood types are A, B, AB and OThe probability that their offspring would have A blood type is 100%. Since one of the parents is homozygous for type A blood while the other is type O

The probability that their offspring would have B blood type is zero (0) since neither of the parents have B antigene

The probability that their offspring would have AB blood type is zero (0) since neither of the parents have B antigene.

The probability that their offspring would have B blood type is zero (0) since only one of the parents have O antigene. The other parent is homozygous for type A, which means the antigens are AA.