You have the following system of equations:
x = 2y - 3
2x - 3y = -5
in order to solve the previous system by elimination, first write the first equation as follow:
x = 2y - 3
x - 2y = -3
next, multiply the previous equation by 2, and subtract the equation to the second one of the system, just as follow:
2(x - 2y = -3)
2x - 4y = -6
2x - 3y = -5
- 2x + 4y = 6
y = 1
next, replace the previous value of y into the expression x = 2y - 3:
x = 2y - 3
x = 2(1) - 3
x = -1
Hence, the solution to the given system of equations is:
x = -1
y = 1