Question

What is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides?

Answer 1

21 cubic inches is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides.

Explanation:

Given: number of cubes(n) = 567 and sides of cubes =
`(1)/(3)` inch.

Volume of cubes states it is found by multiplying the length of any edge by itself twice i,e

Volume of cubes(V) =
`a^3` where a is the sides of the cubes.

then;

Volume of each cubes =
`((1)/(3))^3 = (1)/(27)` cubic inches.

Since, the box that will hold exactly 567 of these cubes.

⇒Volume of box = n
`*` volume of each cubes.

Substitute the given values we get;

Volume of a box =
`567 * (1)/(27) = 21` cubic inches.

Therefore, volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides is, 21 cubic inches.

Answer 2

21 inch³ is the answer hope this helps