Question

hello I need to graph the graph g(x)= x^2+3 which is the inverse of y^2=x-3. I do not know how to graph the graph. :)

Answer 1

Given:

The equation is given as g(x) = x²+3.

The objective is to fin the graph of the equation.

Step-by-step explanation:

Consider the values of x as -2, -1, 0, 1, 2.

At x = -2 in the given equation.

`\begin{gathered} y=(-2)^2+3 \\ =4+3 \\ =7 \end{gathered}`

Thus, the coordinate is (-2,7).

At x = -1 in the given equation,

`\begin{gathered} y=(-1)^2+3 \\ =1+3 \\ =4 \end{gathered}`

Thus, the coordinate is (-1,4).

At x = 0 in the given equation,

`\begin{gathered} y=0^2+3 \\ y=3 \end{gathered}`

Thus, the coordinate is (0,3).

At x = 1 in the given equation.

`\begin{gathered} y=1^2+3 \\ =4 \end{gathered}`

Thus, the coordinate is (1,4).

At x = 2 in the given equation,

`\begin{gathered} y=2^2+3 \\ =7 \end{gathered}`

Thus, the coordinate is (2,7).

To plot the graph:

Then, using the obtained coordinates the graph of the equation will be,

Hence, the graph of the equation is obtained.