Question

The point P is on the unit circle. If the y-coordinate of P is -3/7and P is in quadrant IV, thenT=Question Help: VideoSubmit Question

Answer 1

`x=(√(40))/(7)`

Step-by-step explanation: Provided a point on a unit circle, that has a y-coordinate of y=(-3/7) and lies in the fourth quardrand, we have to find the x-coordinate of the point, the visulization of the problem is as follows:

Using the Pythagorean theorem, the following equation can be constructed:

`\begin{gathered} x^2+(-(3)/(7))^2=1^2 \\ x^2+(-(3)/(7))^2=1^\text{ }\Rightarrow(1) \end{gathered}`

Simplifying the equation (1) gives the following answer:

`\begin{gathered} x^2+(-(3)/(7))^2=1^ \\ x^2=1-(-(3)/(7))^2 \\ x=(√(40))/(7) \end{gathered}`

In conclusion, the answer is:

`x=(√(40))/(7)`