Question

Find the missing factor.3y^2-2y-5=(y+1)( ? )

Answer 1

Given the following function:

`\text{ 3y}^2\text{ - 2y - 5 = (y + 1)(?)}`

Let's determine the missing factor:

`\text{ 3y}^2\text{ - 2y - 5 = (y + 1)(?)}`
`\text{ 3y}^2\text{ - 2y - 5 = (y + 1)(A + B)}`

Where:

`\text{ A = }(3y^2)/(y)\text{ = 3y}`
`\text{ -2y = By + }(1)A`
`\text{ -2y = By + }(1)\text{(3y)}`
`\text{ -2y = By + 3y}`
`\text{ -2y - 3y = By}`
`\text{ -5y = By}`
`\text{ }\frac{\text{-5y}}{\text{ y}}\text{ = }\frac{\text{By}}{\text{ y}}`
`\text{ -5 = B}`

Therefore, the missing factor will be:

(y + 1)(A + B) = (y + 1)(3y - 5)

The answer is 3y - 5