Question

Note: Enter your answer and show all the steps that you use to solve this problem in the space providedA shot put is thrown upward with a velocity of 35 ft/sec. at a height of 4 ft. and an angle of 40°. How longwill it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Accelerationdue to gravity is 32 ft./s². Round your answer to the nearest hundredth.

Answer 1

Given

Initial velocity = 35 ft/sec

Initial height of shot put from horizontal , h' = 4 ft

Angle = 40 degree

Find

Time taken for the shot put to be a horizontal distance of 40 ft. from the person throwing it

Step-by-step explanation

First we find the horizontal component of velocity

Horizontal component of velocity is

`\begin{gathered} u_x=u\cos\theta \\ u_x=35\cos40\degree \\ u_x=26.812(ft)/(sec) \end{gathered}`

the time taken by the shot put to travel a horizontal distance of 40 ft. from the person throwing it is

`\begin{gathered} t=(40)/(u_x) \\ \\ t=(40)/(26.812)=1.4918\approx1.50sec \end{gathered}`

Final Answer

Therefore , the time taken by the shot put to travel a horizontal distance of 40 ft. from the person throwing it is 1.50 seconds