Answer
NO is the answer.
The table does not represent a proportional relationship.
Step-by-step explanation
When two quantities x and y are said to be proportional to each other, this is represented by
y ∝ x
Introducing the constant of variation, k, we have
y ∝ x
y = kx
We can then solve for k knowing that for two proportinal quantities, the value of k will remain the same for corresponding values of x and y
x | y
0 | 2
2 | 4
4 | 6
y = kx
when x = 0, y = 2
y = kx
2 = (k) (0)
2 ≠ 0
This first shows that the two quantities aren't proportional
when x = 2, y = 4
y = kx
4 = (k) (2)
2k = 4
k = 2
when x = 4, y = 6
y = kx
6 = (k) (4)
4k = 6
k = (3/2)
The values of k aren't consistent through the values in the table, hence, we cvan see that this data in the table does not represent proportional relationship.
Hope this Helps!!!