Question

the width of a rectangle is 33 centimeters. the perimeter is atleast 776 centimeters. write and solve an inequality to find the possible lengths of the rectangle

Answer 1

2(33) + 2ℓ ≥ 776; ℓ ≥ 355; A ≥ 33(355)

Explanation:

because

2times 33 is 66

776-66 is 710

710 divided bye 2 is 335

and area is A≥33(355) because area of rectangle is A=33(355)

Plus I just got it right on my quiz.

Answer 2

length is x
p=(33+x)2
(33+x)2 ≥ 776
66+2x ≥ 776
2x ≥ 710
x≥ 355
so the length of the rectangle equals to or is greater then 355:))))