102,209 views
3 votes
3 votes
i need help with my homework PLEASE CHECK WORK WHEN DONENUMBER 10 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

i need help with my homework PLEASE CHECK WORK WHEN DONENUMBER 10 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!-example-1
User Julien Navarre
by
2.6k points

1 Answer

16 votes
16 votes

Answer: B


(log_(2)(4.72))/(0.32)

Step-by-step explanation:

Step 1. The expression that we have is:


P(t)=18,785\cdot2^(0.32t)

This represents the population P after t years.

Step 2. We need to find the expression that represents the amount of time, t, in years, for the population to be 88,740:


P(t)=88,740

Step 3. Substituting this value of P(t) into the given equation:


88,740=18,785\cdot2^(0.32t)

Step 4. To solve for t, first, we divide both sides by 18,785:


(88,740)/(18,785)=2^(0.32t)

The result of the division is:


4.72=2^(0.32t)

Step 5. Then, to continue solving for x, we apply the logarithm base two to both sides:


log_2(4.72)=log_2(2^(0.32t))

We simplify applying this property of logarithms:


log_2(a^x)=x\cdot log_2(a)

The result is:


log_2(4.72)=0.32t\cdot log_2(2^)

And since:


log_2(2^)=1

The expression now is:


log_2(4.72)=0.32t

Step 6. Dividing both sides by 0.32 to solve for t:


(log_2(4.72))/(0.32)=t

This expression is shown in option B:


(log_(2)(4.72))/(0.32)

Answer: B


(log_(2)(4.72))/(0.32)

User Ivan Dokov
by
2.8k points