Question

An unbalanced force of 40. newtons keeps a

5.0-kilogram object traveling in a circle of radius
2.0 meters. What is the speed of the object?
(1) 8.0 m/s (3) 16 m/s
(2) 2.0 m/s (4) 4.0 m/s

Answer 1

(4) 4.0 m/s is the correct answer

Answer 2

4.0 m/s

Step-by-step explanation:

Unbalanced force(F) = 40N

Mass(m) = 5.0kg

Radius(r) = 2.0m

Speed(v)= ???

F = (mv^2)/r

Make v the subject of the formula

mv^2 = Fr

v^2 = Fr / m

v = √Fr/m

v = √(40*2)/5

v = √80/5

v = √16

v = 4.0 m/s