The correct answer for this question is 22.32 g H2O. First, we need to establish the mass of H2O, which is H2O = 2 (1.00G H) + (16.00g O), which is equal to 18.00g/mol. Using factor labels you can then match and eliminate the labels of each number. 18.00g I 1.24 mol------------I----------------1 mol. Here we can observe that the mols cancel each other out, so this means that as a result you are left with 18.00gx1.24, which gets you to your answer of 22.32g H2O.