Question

A chemist dilutes a 1.0 mL sample of 2.0 M KNO3 by adding water to it. If the concentration of the solution that is obtained is 0.0080 M, what is its volume?

Use: Mi Vi = Mf Vf

A.) 125 mL
B.) 250 mL
C.) 500 mL
D.) 2,000 mL

Answer 1

Answer: Option (B) is the correct answer.

Step-by-step explanation:

The given data is as follows.

`M_(1)` = 2.0 M,
`V_(1)` = 1.0 ml

`M_(2)` = 0.008 M,
`V_(2)` = ?

Therefore, calculate the volume of given solution as follows.

`M_(1) * V_(1)` =
`M_(2) * V_(2)`

Now, putting the given values into the above formula as follows.

`M_(1) * V_(1)` =
`M_(2) * V_(2)`

`2.0 M * 1.0 ml` =
`0.008 M * V_(2)`

`V_(1)` = 250 ml

Therefore, volume of the solution obtained is 250 ml.

Answer 2

Mi = 2.0 M

Vi = 1.0 mL

Mf = 0.0080 M

Vf = ?

Mi * Vi = Mf* Vf

2.0 * 1.0 = 0.0080 * Vf

2 = 0.0080* Vf

Vf = 2 / 0.0080

Vf = 250 mL

answer b

hope this helps!.