Question

Hello! I need some assistance with this homework question for precalculus, please?HW Q20

Answer 1

According to the logarithm definition:

`\log_bc=a\Leftrightarrow b^a=c`

In this question:

`\begin{gathered} 3.6=6^x \\ which\text{ }is\text{ }the\text{ }same\text{ }as \\ 6^x=3.6 \end{gathered}`

Then, comparing with the definitionm:

a = x

b = 6

c = 3.6

And, transforming to the log form:

`\begin{gathered} \begin{equation*} \log_bc=a \end{equation*} \\ \log_6(3.6)=x \end{gathered}`

Answer: