Question

Which equation can be solved to find one of the missing side lengths in the triangle?aB60512 unitsАCOS(60°) =22 믕cos(60°) = 12SubmitNex응Save and Exitcos(609) =0=1or this and return

Answer 1

In a right rectangle, we have:

`\sin \alpha=(opposite)/(hypotenuse)`
`\cos \alpha=\frac{\text{adjacent}}{hypotenuse}`

For your exercice, hypotenuse=12

The exercise also inform the angle 60°, then:

`\sin \text{ 60}=\frac{\text{opposite}}{\text{hypotenuse}}=(b)/(12)`
`\cos 60=\frac{adjacent}{\text{hypotenuse}}=(a)/(12)`