Question

An MP3 player draws a current of 0.120 ampere

from a 3.00-volt battery. What is the total charge
that passes through the player in 900. seconds?
(1) 324 C (3) 5.40 C
(2) 108 C (4) 1.80 C

Answer 1

The Definition of Electrical Current is given by:


`i= (\Delta Q)/(\Delta t)`

Entering the unknowns:


`i= (\Delta Q)/(\Delta t) \\ \Delta Q=0.12*900 \\ \boxed {\Delta Q=108C}`

Number 2

If you notice any mistake in my english, please let me know, because i am not native.

Answer 2

Answer: (2) 108 C

Step-by-step explanation:

Electric charge of 1 coulomb has said to have passed when a current of 1 Ampere is passed for 1 second.

`Q=I* t`

Q= charge in coloumb = ?

I = current in amperes = 0.120 A

t= time in seconds = 900 sec

`Q=0.120A* 900sec=108C`