Question

What is the equation of the line that passes through the points (-2,2) and (0,5)?

Answer 1

`(-2,2), \ \ \ (0,5)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \\ \\m=( 5-2)/(0+2) = (3)/(2) \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_(1) =m(x-x _(1))\\\\m=(3)/(2), \ \ x_(1)=-2, \ \ y_(1)=2 \\ \\y- 2 = (3)/(2) (x+2)\\\\y=(3)/(2)x +3+2 \\ \\y=(3)/(2)x + 5`