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Three consecutive multiples of 7 have a sum of 126.

What is the greatest number?

1 Answer

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7n+7n+7+7n+14=126\\ 21n+21=126\\ 21n=105\\ n=5\\\\ 7\cdot5+14=49

The greatest is 49.



2n+2n+2+2n+4=84\\ 6n+6=84\\ 6n=78\\ n=13\\\\ 2\cdot13=26

The least is 26.
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