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At 27.00 °C a gas has a volume of 6.00 L. What will the volume be at 150.0°C?

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We use Charles's rule for this problem: V1/T1=V2/T2

Remember that the temp is in Kelvin:
27.0 degrees Celsius= 300K, 150.0 degrees Celsius= 423K

V1/T1=V2/T2
⇒ (6.00L)*(300K)= V2* (423K)
⇒ V2= (6.00L)*(300K)/(423K)
V2= 4.26L

Hope this would help~
User Musonda
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