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24 votes
Match the angle on the left with its appropriate measure onthe right.

Match the angle on the left with its appropriate measure onthe right.-example-1
User Jonas Granvik
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1 Answer

21 votes
21 votes

From the given image we have,


\begin{gathered} \angle BCX=40^(\circ) \\ \angle ABC=40^(\circ) \end{gathered}

Therefore, angle GCF is which is opposite to angle BCX


\angle GCF=40^(\circ)

Now,


\angle ABC+\angle EBL+\angle CBX=180^(\circ)
\begin{gathered} 40\text{ + 90 + }\angle CBX=180^(\circ) \\ \angle CBX=180-130 \\ \angle CBX=50^(\circ) \end{gathered}
Now,\angle BXC=\angle LBX
\angle BXC=90^(\circ)

User KamilCuk
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