Question

The function h is defined by h(y)=4|y+2|-3 . what is the value of h(-8)

Answer 1

Given

`h(y)=4|y+2|-3`

For y=-8

The function has absolute values, this means that is V shaped.

It is defined for Y, this means that it opens vertically.

From the equation, that is written in vertex form, we can determine that the coordinates of its vertex is (-3,-2)

And the coefficient that multiplies the absolute term is positive, which indicates that the function opens to the right (+ infinite)

To calculate h(-8) you have to replace the formula with y=-8

`\begin{gathered} h(-8)=4|-8+2|-3 \\ h(-8)=4|-6|-3 \\ h(-8)=4\cdot6-3 \\ h(-8)=24-3 \\ h(-8)=21 \end{gathered}`