Question

Find three consecutive integers whose sum is negative twelve. Set up an equation and solve

Answer 1

x + (x+1)+ (x+2) = -12

3x+3 =-12

Solve for x

3x =-12-3

3x=-15

Divide both sides by 3:

3x/3 = -15/3

x = -5

First integer is -5

Second is integer -5+1 =-4

Third integer -5+2 = -3