Question

How many combinations are possible assume the items are distinct 7 items chosen 5 times

Answer 1

Case: Combination

Method:

distinct 7 items chosen 5 times

Selecting 5 from 7 items is:

`\begin{gathered} 7C_5 \\ (7!)/((7-5)!5!) \\ (7!)/(2!*5!) \\ (7*6*5!)/(2*1*5!) \\ (7*6)/(2*1) \\ (42)/(2) \\ =21 \end{gathered}`

Final answer:

There are 21 ways 5 items can be selected from 7 distict items