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6 votes
6 votes
Please help with this problem:Solve for b.16 = a^2 + b^2A. b = 16 − a2B. b = ±16−a^2−−−−−−√C. b = ±16+a^2−−−−−−√D. b = 4−a

Please help with this problem:Solve for b.16 = a^2 + b^2A. b = 16 − a2B. b = ±16−a-example-1
User Jijo Paulose
by
3.0k points

1 Answer

15 votes
15 votes

SOLUTION

We want to solve for b in the equation


16=a^2+b^2

Solving we have


\begin{gathered} 16=a^2+b^2 \\ we\text{ will move a}^2\text{ to meet 16, we have } \\ 16-a^2=b^2 \\ b^2=16-a^2 \\ move\text{ the square to the other side, it becomes square root, we have } \\ b=\pm√(16-a^2) \end{gathered}

Hence the answer is the second option

User Cachonfinga
by
2.9k points
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