Question

Write the equation of the points: (10, -28) and (4, -4) using y=mx+b

Answer 1

We have the following points given:

(x1 =10, y1= -28) (x2= 4, y2=-4)

We can find the slope of the line like this:

`m=(y_2-y_1)/(x_2-x_1)=(-4-28)/(4-10)=(32)/(6)=(16)/(3)`

And the intercept can be founded on this way:

`-4=(16)/(3)(4)+b`

Solving for b we got:

`b=-(64)/(3)-4=-(76)/(3)`

Then the equation would be:

`y=(16)/(3)x-(76)/(3)`