Question

Can you please help i cant seem to find the answer

Answer 1

Given data:

* The force on the left side of the tank is,

`F_1=\text{0}.644\text{ N}`

* The area of the left side of the tank is,

`A_1_{}=12.809m^2`

* The area of the right side of the container is,

`A_2=43.95m^2`

Solution:

According to the Pascal's law, the pressure on the left side of the tank is equal to the pressure on the right side of the tank.

The pressure in the terms of the force is,

`P=(F)/(A)`

where F is the force, and A is the area,

Thus, from the pascal's law,

`\begin{gathered} P_1=P_2 \\ (F_1)/(A_1)=(F_2)/(A_2) \\ F_2=A_2*(F_1)/(A_1) \end{gathered}`

Substituting the known values,

`\begin{gathered} F_2=43.95*(0.644)/(12.809) \\ F_2=2.21\text{ N} \end{gathered}`

Thus, the value of force on the right side of the tank is 2.21 N.