Andrew can paint the neighbour's house 3 times as fast as Bailey. The year Andrew in Bailey work together, it took them 4 days. How long would it take each to paint the house?
Let
x -----> Andrew's time to paint the house
y ----> Balley's time to paint the house
we have that
x+y=4 ------> equation A
x=y/3 -----> equation B
substitute equation B in equation A
(y/3)+y=4
solve for y
(4/3)y=4
y=3 days
x=3/2=1 day
therefore
Andrew's time to paint the house is 1 day
Balley's time to paint the house is 3 days