Question

Find the equation of a line that goes through the point ( 1, - 1 ) and is parallel to the line y = - 6x + 1Select one:a.y = - 6x - 11b.y = - 5x + 2c.y = - 1 / 6x + 1d.y = - 6x + 5

Answer 1

To find the equation of a line that passes through a point and parallel to another line, we can use the point-slope form.

`y-y_1=m(x-x_1)`

First, let's find out what the slope m should be. Remember that parallel lines have the same slope.

`\begin{gathered} y=mx+b \\ y=-6x+1 \end{gathered}`

We see that the slope is -6.

Now that we have the slope, we just need to plug in the coordiantes of the point and the slope to the point-slope format of the equation. Then, we will rewrite it in point-intercept form.

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(-1)=-6(x-1) \\ y+1=-6(x-1) \\ y+1=-6x+6 \\ y=-6x+5 \end{gathered}`

The answer is y = -6x + 5.