Question

. Find the Value of x. SHOW YOUR WORK OR NO CREDITIMI

Answer 1

we can use pythagoras to solve the triangle

`a^2+b^2=h^2`

where a and b are sides and h the hypotenuse on this case we use half triangle to make a rigth triangle and apply pythagoras

a is 9, b is 20 and h the x

so replacing

`\begin{gathered} 9^2+20^2=x^2 \\ \end{gathered}`

solve for x

`x=\sqrt[]{9^2+20^2}`

and do the operatios

`\begin{gathered} x=\sqrt[]{81+400} \\ x=\sqrt[]{481}\approx21.93 \end{gathered}`

the value of x is 21.93 units