Find all real numbers x such that x^4 ≤ 8x^2 − 16.

asked Jan 23, 2015 204k views

4 votes

Find all real numbers x such that
x^4 ≤ 8x^2 − 16.

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$x^4 \leq 8x^2 -16\\ x^4-8x^2+16\leq0\\ (x^2-4)^2\leq0\\ x^2-4=0\\ x^2=4\\ x=-2 \vee x=2$

MikaelHalen answered Jan 27, 2015

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