Question

The 2000 Belmont Stakes winner, Commendable, ran the horse race at anaverage speed of 15.98 m/s. If Commendable and jockey Pat Day had acombined mass of 550.0 kg, what was their KE as they crossed the finish line?

Answer 1

Given:

The combined mass is

`m=550.0\text{ kg}`

The speed is

`v=15.98\text{ m/s}`

Required: find the kinetic energy.

Step-by-step explanation:

To find the kinetic energy we will use the formula that is given as

`K.E=(1)/(2)mv^2`

Here,

`m`

is the mass and

`v`

is the speed.

Plugging all the values in the above relation, we get

`\begin{gathered} K.E=(1)/(2)mv^2 \\ K.E=(1)/(2)*550.0\text{ kg}*(15.98\text{ m/s})^2 \\ K.E=0.5*550.0\text{ kg}*255.36\text{ }(\text{m/s}^)^2 \\ K.E=70224.11\text{ J} \end{gathered}`

Thus, the kinetic energy is 70224.11 J.