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Probability questionA medical clinic has a crew of 5, two of which have been infected with a virus althoughthey show no symptoms. If you select two crew members for a task, what is the probabilitythat there is at least one infected person in group assigned for the task.

User Wayne Hartman
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1 Answer

11 votes
11 votes
Answer:

The probability that there is at least one infected person in group assigned for the task = 0.7

Step-by-step explanation:

Total number of crew members = 5

Number of infected persons = 2

Number of uninfected persons = 3

Probability that there is at least one infected person will be:

P(at least 1 infected) = P(1 infected) + P(2 infected)

Probability of selecting 1 infected person


\begin{gathered} P(1\text{ infected person\rparen=}(2C1*3C1)/(5C2) \\ \\ P(1\text{ infected person\rparen =}(2*3)/(10) \\ \\ P(1\text{ infected person\rparen =0.6} \end{gathered}
\begin{gathered} P(2\text{ }\imaginaryI\text{nfected persons}\operatorname{\rparen}=\frac{\text{2C2}}{\text{5C2}} \\ \\ P(2\text{ infected persons\rparen =}(1)/(10) \\ \\ P(2\text{ infected persons\rparen = 0.1} \end{gathered}

P(at least 1 infected) = P(1 infected) + P(2 infected)

P(at least 1 infected) = 0.6 + 0.1

P(at least 1 infected) = 0.7

The probability that there is at least one infected person in group assigned for the task = 0.7

User Abbii
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