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Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.

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k:12x-5y=2\to-5y=-12x+2\ \ \ /:(-5)\to y=(12)/(5)y-(2)/(5)\\\\l:y=mx+b\\\\k\ ||\ l\iff m=(12)/(5)\\\\ l:y=(12)/(5)x+b;\ (2;\ 3)\\\\(12)/(5)\cdot2+b=3\\\\(24)/(5)+b=3\\\\b=(15)/(5)-(24)/(5)\\\\b=-(9)/(5)\\\\Answer:y=(12)/(5)x-(9)/(5)\to(12)/(5)x-y=(9)/(5)\ \ \ \ /\cdot5\to12x-5y=9
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