Question

Calculate the heat released when 1200 g of steam changes phase to liquid water. Assume no temperature change and Hv = 2260J/g

Answer 1

According to the explanation given in the previous session, now we have a similar situation, but now we have steam changing to liquid water and a release of heat and not absorption. The formula will be the same:

Q = m * ΔHv

We have:

m = 1200 grams

ΔHv = 2260 J/g, but since we are releasing energy, this value has to be negative, -2260 J/g

Now we add these values into the formula:

Q = 1200 * -2260

Q = - 2712000 Joules or 2712 Kilojoules