Question

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. If this player shoots twice, the exact probability that he scores a goal both times is

Answer 1

If he misses 63%, then he makes it 37% each time he shoots.
To calculate the probability if he makes it both times, you multiply it together:
37% * 37% = 13.69%

Answer 2

The probability of scoring two goals in both times is 0.137 or 13.7%

Explanation:

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

So
`P(A)=0.63`

Hence, the probability of getting success in his shoots will be,

`P(A^c)=1-P(A)=1-0.63=0.37`

The probability of scoring two goals in both times is,

`=P(A^c)\cdot P(A^c)`

`=0.37* 0.37`

`=0.137`

`=13.7\%`