Question

three packages of coffee cost a total of $10.20 the first cost $0.30 more than the second and the second cost $0.66 less than the third how much did the second package cost

Answer 1

3.08$

Explanation:

Lets solve this problem using an algebraic equation.

In this case, I am using the variable "x" as the second package of coffee.

First: x+0.3

Second: x

Third: x+0.66

Setting up the equation. All packages of coffee add up to $10.20.

x+x+0.3+x+0.66 = 10.20

Combine like terms.

3x + 0.96 = 10.20

Subtract 0.96 on both sides.

3x = 9.24

Divide 3 on both sides.

x=3.08