menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
Divide 33 photos into two groups so the ratio is 4 to 7
asked
Oct 13, 2016
149k
views
1
vote
Divide 33 photos into two groups so the ratio is 4 to 7
Mathematics
middle-school
TechTravelThink
asked
by
TechTravelThink
7.4k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
2
Answers
4
votes
4:7
4x:7x
4x+7x=11x
11x=33
x=3
4x3=21
7x3=21 so 12 and 21 are in a ratio and add up to 33 hope i helped
Sushant Rajbanshi
answered
Oct 13, 2016
by
Sushant Rajbanshi
9.0k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
6
votes
33 photos in a 4x to 7x ratio
4x + 7x = 33
11x = 33
x = 3
33 photos can be put in a 4(3) to 7(3) ratio
which is a 12 to 21 ratio
so 12 photos on one side, and 21 on the other side to get the ratio of 4 to 7
Note:
a(b) = ab = a x b = a times b
Hesam Qodsi
answered
Oct 18, 2016
by
Hesam Qodsi
8.2k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.5m
questions
12.2m
answers
Other Questions
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement how thick must the cement be to cover field
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org