344,184 views
16 votes
16 votes
Rectangle A has a perimeter of 20 centimeters and an area of V 247 square centimeters, Rectangle B has a perimeter of centimeters and an area of square centimeters.

User Dolanor
by
3.2k points

1 Answer

16 votes
16 votes

Given:

Ths length of the rectangle B is, l = 8 cm.

The breadth of the rectnagle is, b = 1 cm.

The objective is to find the Perimeter and Area of the rectangle B.

The perimeter of the rectangle B can be calculated as,


\begin{gathered} P=2(l+b) \\ =2(8+1) \\ =2(9) \\ =18\text{ cm} \end{gathered}

The area of the rectangle B can be calculated as,


\begin{gathered} A=l* b \\ =8*1 \\ =8cm^2 \end{gathered}

Hence, the perimeter of the reaaaaacngle is, 18 cm and the area of the rectangle is 8 square centimeters.

User Rpechayr
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.